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=-16Y^2+12Y-3.25
We move all terms to the left:
-(-16Y^2+12Y-3.25)=0
We get rid of parentheses
16Y^2-12Y+3.25=0
a = 16; b = -12; c = +3.25;
Δ = b2-4ac
Δ = -122-4·16·3.25
Δ = -64
Delta is less than zero, so there is no solution for the equation
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